JAVÍTÁSI-ÉRTÉKELÉSI ÚTMUTATÓ MARKSCHEME

ÉRETTSÉGI VIZSGA

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2005. május 20.

Biológia angol nyelven

középszint Javítási-értékelési útmutató 0513

BIOLÓGIA ANGOL NYELVEN BIOLOGY KÖZÉPSZINTŰ ÍRÁSBELI VIZSGA STANDARD LEVEL WRITTEN EXAMINATION Az írásbeli vizsga időtartama: 120 perc Duration of written examination: 120 minutes

JAVÍTÁSI-ÉRTÉKELÉSI ÚTMUTATÓ MARKSCHEME OKTATÁSI MINISZTÉRIUM MINISTRY OF EDUCATION

Biológia angol nyelven — középszint

Javítási-értékelési útmutató

Instructions – How To Mark The Standard Level Paper 1. 2. 3. 4. 5. 6. 7. 8.

Always use red ink . Tick correct answers. Each tick is equivalent to 1 point. You can not give half the point. Indicate with two ticks, if the candidate answered correctly an assignment of two points. Please accept the answer, if it is correct, but not mentioned in the Answer Key. The same procedure should be applied in the case of synonyms (e.g.: platelets – thrombocytes). In the Answer Key equally acceptable answers are separated with backslash (/) from one another. At the end of the assignment add the points up in the grey-coloured chart . At the end indicate the detailed points for each assignment in the final summary chart and add them up to indicate the total score. The total point multiplied by 1.25 will give the total point for the written part of exam. The final evaluation is the total point for the written part of the exam expressed in percentage. If the candidate was asked to compose whole sentences (e.g.: giving reasons or explanations) – only grammatically correct sentences are acceptable. Please, do not deduct points for spelling mistakes, yet do not accept misleading compositions.

We wish you a successful work.

írásbeli vizsga 0513

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I. Proteins and nucleic acids

8 points

Each correct answer is awarded by one point. 1. 2. 3. 4. 5. 6. 7. 8.

Its monomers are aminoacids. It is a constituent of chromosomes. Ribosomes play role in its synthesis. Its monomers are linked by peptide bonds. Cellulose belongs to this group. It is a macromolecule. It is able to duplicate (replicate) itself. It is a constituent of viruses.

II. Vision and vision disorders 1. 2. 3. 4. 5. 6.

A C A A D C B/D C

6 points

far-sighted / short-sighted (any answer is acceptable) convex / concave (any answer is acceptable) D ciliary body contract becomes more round

III. Blood groups and their inheritance

1 point 1 point 1 point 1 point 1 point 1 point

11 point

1. He/she can get blood of the same blood group only. /in case of emergency: AB: from everybody, A: from A and 0, B: from B and 0, 0: only from 0. (Both answers are acceptable, but in the second case it must be noted that it applicable only in emergency.) 1 point 2. C 1 point 1 point 3. Éva: IAI0 Ádám: I BI0 1 point 4. Non-identical/dizygotic twins 1 point 5. Because their Rh blood groups are different. 1 point 6. Either A or B. (Only if both are named.) 1 point 7. In the course of the delivery of the baby (childbirth) Rh antigen got into the blood of the mother and she would produce antibodies against them, which would destroy the red blood cells/corpuscles of future Rh+ child (embryo). The treatment prevents this. (Other correct phrasings are also acceptable.) 1 point 8. Dd (heterozygote). 1 point 9. Yes, it is possible. 1 point if both parents are heterozygotes. 1 point


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IV. The evolution of vascular plants

8 points

Each number written in the correct place is awarded by 1 point. If the same number is put next to more plant groups no point can be awarded. Pteridophytes: 2, 3 Gymnosperms: 4, 5, 8 Angiosperms: 1, 6, 7

V. The behaviour of the brick-layer bee

6 points

1. (1 point can only be awarded for the whole row of letters) E

D

C

A

B

2. 3. 4. 5.

The arrow put between behavioural element A and B is awarded by 1 point. D Because the subsequent generations do not come into contact with their parents. After the interruption the bee would only carry out the unburdening of the pollen (and would not attempt to empty its already empty honey crop). Other correct phrasings are also acceptable. 6. Fabre interfered in the course of events deliberately. Other correct phrasings are also acceptable.

VI. The environment and the body structure of Reptiles

10 points

1. 2. 3. 4. 5. 6.

A A A B A As a consequence of internal fertilisation the reproduction is independent of water/ Eggs make embryonic development in dry environments possible. / The hatching of eggs depends on the temperature of the environment and the number of hours of sunshine. / The number of eggs depends on the amount of food available. (Any of them are acceptable.) 7. The cornified epithelium prevents dehydration. / In the summer its body is heated up by the sun, in the winter it is compelled to have a dormant period. (Any of them are acceptable.) 8. The cornified epithelium does not make cutaneous (skin) respiration possible. / Only a lung of sufficient internal surface area can provide adequate oxygen supply. (Any of them are acceptable.) 9. The body temperature and the intensity of metabolism depends on the temperature of the external environment. 10. The integumentum is not capable of keeping internal heat in a cooling external environment. (body temperature is adjusted to external temperature.) / Changing body temperature makes insulating layers superfluous/unnecessary.


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6–10. All logical reasonings are acceptable!

VII. Our bad habit of eating titbits and nibbling 1. potato starch, glucose syrup (only if both are named) 2. glucose (syrup) 3. No. The distributor did not identify the colourings. (acceptable only with reasoning) 4. A 5. D 6. C 7. B 8. The mass of the consumed product is 75g, 1600kJ/100g*75g= 1200kJ The description of the calculation is awarded by 1 point, the result is awarded by 1 point. 9. A) D) (only if both are named)

VIII. Two types of forest 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11.

1 point 1 point 1 point 1 point 1 point 1 point 1 point 2 points 1 point

11 points

C 1 point B 1 point A 1 point A 1 point B 1 point A 1 point D 1 point C 1 point On the axis X: diameter of tree trunks / the estimated age of trees. 1 point On the axis Y: frequency/percentage/their number. 1 point Since the trees in the poplar plantation were planted at the same time their age is the same, while in a semi-natural forest this is not the case/ In natural state young and old, decaying trees coexist while in plantations this is not the case. 1 point (Other correct phrasings of the same content are also acceptable.)

IX. The oxygen cycle in nature 1. 2. 3. 4. 5. 6. 7. 8. 9. 10.

10 points

10 points

water photosynthesis producing oxygen producers decomposers heterotrophic organisms cellular respiration carrier molecules oxygen is released into the environment


1 point 1 point 1 point 1 point 1 point 1 point 1 point 1 point 1 point 1 point

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Sources of texts and pictures: II.:

Id. Peter Brueghel: A festő és a műértő. (1565). In: E. H. Gombrich. A művészet története. Gondolat, Budapest, 1978. V.: J. H. Fabre: A rovarok környezete és viselkedése. Kriterion, Bukarest, Téka sorozat, 1979. VI.: Zöld gyík: Both–Kovács–Revákné: Biológia munkafüzet I., Nemzeti Tankönyvkiadó, Budapest, 2003.


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